[tex]3 \sqrt{256 \ \times x^{10} y^{7} }[/tex]
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square root of 256 is 16 :
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[tex]= 48 \sqrt{x^{10} y^{7}}[/tex]
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√10¹⁰ = 10⁵ :
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[tex]= 48x^5 \sqrt{ y^{7}}[/tex]
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√y⁶ = y³ :
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[tex]= 48x^5y^3 \sqrt{ y}}[/tex]
