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  • 04-02-2018
  • Mathematics
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Cos x+ 2cosx + Sinx=0 solve the equation for the interval [0,2pi]

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Аноним Аноним
  • 04-02-2018
cos²(x) + 2cos(x) + sin²(x) = 0
 Note: cos²(x) + sin²(x) = 1
2cos(x) + 1 = 0
2cos(x) = -1
cos(x) = [tex]- \frac{1}{2} [/tex]
120 degrees and 240 degrees → [tex] \frac{2}{3} \pi [/tex] and [tex] \frac{4}{3} \pi [/tex]
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