ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?

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02-08-2017
Mathematics

contestada

ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?

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choixongdong choixongdong · Answer 1 · 2017-08-02T18:49:05+02:00

choixongdong choixongdong

02-08-2017

41*41 = 1681
40*40 = 1600
9* 9 = 81
so a^2 = b^2 + c^2
1681 = 1600 + 81
1681 = 1681 ...it's right triangle

CA = 41 = Hypo.
cosC = Adj / Hypo
cosC = BC / CA = 40/41

answer
cosC = 40/41

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caballerosdaniel007 caballerosdaniel007 · Answer 2 · 2020-02-03T19:38:27+01:00

caballerosdaniel007 caballerosdaniel007

03-02-2020

Answer:

The correct answer is

C 40/41

Step-by-step explanation:

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