garydesir1
garydesir1 garydesir1
  • 04-07-2017
  • Mathematics
contestada

Hello - I have one last question that I think you might be able to help me with. Thanks~

Hello I have one last question that I think you might be able to help me with Thanks class=

Respuesta :

ARYANAGARWAL ARYANAGARWAL
  • 04-07-2017
Let slant height be s
Height = 38yd. = h
Side = 42yd. = a

S² = h² + (a/2)²
= 38² + 21²
= 1444 + 441
= 1885
S = √1885
S = 43.42yd.

Lateral area = 1/2 × 4a × s
= 2 × 42 × 43.42
= 3646.99
= 3647 yd.²
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gorraricardezju
gorraricardezju gorraricardezju
  • 05-07-2017
Hello Gary!

In Short, The Correct Answer would be: Option "D". 3647 yd^2

Because: Base edge = 42 and Height = 38

So then, AL=a√a^2+4h^2=42·√42^2+4·38^2≈3646.99328. (3647 rounded up)

AL≈3646.99


Hope this Helps! Have A Wonderful Day! :)
Answer Link

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