nopesixteen16 nopesixteen16

01-06-2017
Mathematics

contestada

excluded values for y=5/(6x-72)
(the / is a fraction so its 5 over 6x)

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01-06-2017

The denominator cannot equal zero. Set the expression on the denominator = to zero to find the value that must be excluded.
6x - 72 = 0
add 72 to both sides
6x = 72
Divide both sides by 6
x = 9
The excluded value is 9.

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