RenataF453377 RenataF453377
  • 03-11-2022
  • Mathematics
contestada

Write an equation in slope-intercept form for the line perpendicular to the given line that passes through the origin. y = 11/5 x + 7

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TaniahQ22590 TaniahQ22590
  • 03-11-2022

y = 11/5 x + 7

Slope intercept form:

y=mx+b

Where:

m= slope

b= y-intercept

So, for the line given:

m= 11/5

b= 7

Perpendicular lines have negative reciprocal slopes.

negative reciprocal of 11/5 = -5/11

Slope = -5/11

So far we have:

y= -5/11 + b

Since it passes through the origin (0,0) replace and solve for b:

0= -5/11(0) +b

b=0

Final expression:

y= -5/11x

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