KiarrahI483474 KiarrahI483474
  • 03-11-2022
  • Mathematics
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A circle is centered at (5,-3) and has a radius of 16.Complete the equation of the circle.=;.: 4:: 16:: (y - 3):: 256:: (x – 5):: (x + 5)2:: (y + 3)2

A circle is centered at 53 and has a radius of 16Complete the equation of the circle 4 16 y 3 256 x 5 x 52 y 32 class=

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BrelynnC50308 BrelynnC50308
  • 03-11-2022

The equation of the circle centered at (h,k) with radius r is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

In this case, the center is (5, -3) and the radius is 16, then the equation is:

[tex]\begin{gathered} (x-5)^2+(y-(-3))^2=16^2 \\ (x-5)^2+(y+3)^2=256 \end{gathered}[/tex]

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