AedanU654295 AedanU654295
  • 03-11-2022
  • Mathematics
contestada

If f(x)=x^2-5x+1 , find f(t+2)

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GwendalynnS417858 GwendalynnS417858
  • 03-11-2022

Given that:

[tex]f(x)=x^2-5x+1[/tex]

Therefore:

[tex]f(t)=t^2-5t+1[/tex]

To find f(t+2), we replace t with t+2 in f(t).

[tex]f(t+2)=(t+2)^2-5(t+2)+1[/tex]

We can then simplify:

[tex]\begin{gathered} f(t+2)=(t+2)^2-5(t+2)+1 \\ =(t+2)(t+2)-5t-10+1 \\ =t^2+2t+2t+4-5t-10+1 \\ =t^2-t-5 \end{gathered}[/tex]

Therefore:

[tex]f(t+2)=t^2-t-5[/tex]

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