AlonieR188941 AlonieR188941
  • 03-11-2022
  • Mathematics
contestada

Solve the system by any method you choose: .No solution exists.There are an infinite number of solutions.(0, –1)(1, 0)

Solve the system by any method you choose No solution existsThere are an infinite number of solutions0 11 0 class=

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AbdulkadirX249317 AbdulkadirX249317
  • 03-11-2022

We are given the following system of equations

[tex]\begin{gathered} -\frac{1}{2}x-4y=4 \\ 2x+16y=2 \end{gathered}[/tex]

Let us solve the above system of equations using the elimination method.

Suppose we want to cancel the x terms, then we have to multiply eq.1 by 4.

[tex]4\cdot(-\frac{1}{2}x-4y=4)\Rightarrow-2x-16y=16[/tex]

Now, add the two equations

As you can see, after adding the equations we get 0 = 18 which cannot be true.

This means that no solution exists for this system of linear equations.

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