AnnaraeU173969 AnnaraeU173969
  • 03-11-2022
  • Mathematics
contestada

If Corey has 2 times as many nickels as dimes and they have a combined value of 80 cents, how many of each coin does he have? dimes nickels

Respuesta :

ZylinE61637 ZylinE61637
  • 03-11-2022

Given:

Corey has 2 times as many nickels as dimes

Let the number of nickels = x

Let the number of dimes = y

So,

[tex]x=2y[/tex]

and they have a combined value of 80 cents

[tex]5x+10y=80[/tex]

Substitute from x = 2y

so,

[tex]\begin{gathered} 5\cdot2y+10y=80 \\ 10y+10y=80 \\ 20y=80 \\ y=\frac{80}{20}=4 \\ x=2y=8 \end{gathered}[/tex]

so, the answer wil be:

dimes = 4

nickels = 8

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