jazzycheri jazzycheri
  • 04-01-2017
  • Mathematics
contestada

How do I find the critical points?

[tex]( x^{2} - 1)^3 [/tex]

Intervals: [ -1, 2]

Respuesta :

Hilltop1108 Hilltop1108
  • 04-01-2017
Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

[tex] \frac{d}{dx}(x^{2} - 1)^{3} [/tex]

So we apply chain rule:

= [tex]3(x^{2} - 1)^{2} * 2x[/tex]

Set our first derivative to zero and solve for x:

3(x^2 - 1) * 2x = 0

So we can see that (by plugging in) 0, -1 and 1 makes our solution true

So our critical value is x = 0, x = -1, x = 1
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