ltztellexx ltztellexx

04-08-2021
Physics

contestada

A force of 100 N stretches a spring by 5cm. Calculate the work done.

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Аноним Аноним

04-08-2021

Answer:

Work done is 5 J

Explanation:

Workdone = Force × distance

[tex]{ \sf{W = 100 \times (5 \times {10}^{ - 2}) }} \\ { \sf{W = 5 \: joules}}[/tex]

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