Thanh312529 Thanh312529
  • 04-08-2021
  • Mathematics
contestada

6cos(20πt-π)+6√3cos(20πt-π\2)

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Аноним Аноним
  • 04-08-2021

Answer:

Answer is -6t

Step-by-step explanation:

[tex]{ \tt{ = (6 \cos(20\pi t) \cos(\pi) + 6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t) \cos( \frac{\pi}{2} ) + \sin(20\pi t) \sin( \frac{\pi}{2} )) }} \\ = { \tt{ (- 6t + 0) + (0 + 0)}} \\ = { \tt{ - 6t}}[/tex]

Note that π is 180°

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