julissadiaz8757
julissadiaz8757 julissadiaz8757
  • 01-06-2021
  • Mathematics
contestada

Solve the expression for a=12 , b=6 and c=3

Solve the expression for a12 b6 and c3 class=

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sreedevi102
sreedevi102 sreedevi102
  • 01-06-2021

Answer:

48

Step-by-step explanation:

[tex]a = 12, \ b = 6, \ c = 3\\\\b^2 - c^2 + (a+ b+c) = 6^2 - 3^2 + (12 +6+3) = 36-9+21 = 48[/tex]

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Аноним Аноним
  • 01-06-2021

Answer:

2-12+(++)

b^{2}-1c^{2}+(a+b+c)

b2−1c2+(a+b+c)

Simplify: 1

Eliminate redundant parentheses

2−12+(++)

b^{2}-1c^{2}+(a+b+c)

b2−1c2+(a+b+c)

2−12+++

b^{2}-1c^{2}+a+b+c

b2−1c2+a+b+c

Solution: 2−12+++

b^{2}-1c^{2}+a+b+c

b2−1c2+a+b+c

Answer Link

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