StephanieCrown
StephanieCrown StephanieCrown
  • 03-05-2021
  • Mathematics
contestada

Solve
f(x)=2x^2+6, fund the value if f(x+3)​

Respuesta :

nashshii
nashshii nashshii
  • 03-05-2021

Answer:

F=2x^2+24

Step-by-step explanation:

F (x+3)=2x^2+6

F=2(x+3)^2+6

F=2(X^2+9)+6

F=2x^2+18+6

F=2x^2+24

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