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01-12-2020
Mathematics

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If (n+1)!=90×(n-1)!,find n.

Respuesta :

01-12-2020

[tex]\displaystyle\bf\\(n+1)!=90\times (n-1)!\\\\(n-1)!\times n\times(n+1)=90\times (n-1)!~~~\Big|~:(n-1)!\\\\n(n+1)=90\\\\n(n+1)=9\times10\\\\n(n+1)=9(9+1)\\\\\implies~~\boxed{\bf n=9}[/tex]

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