amirredzepagic10 amirredzepagic10
  • 04-08-2020
  • Chemistry
contestada

When NaOH is added to water, the [OH-] = 0.04 M. What is the [H3O+]?

Respuesta :

Stephen46
Stephen46 Stephen46
  • 10-08-2020

Answer:

The answer is

[H3O+] = 2.51 × 10^-13 M

Explanation:

To find the [H3O+] in the solution we must first find the pOH and the pH of the solution

That's

pH + pOH = 14

pH = 14 - pOH

To find the pOH we use the formula

pOH = - log [OH-]

[OH-] = 0.04 M

pOH = - log 0.04

pOH = 1.4

So the pH is

pH = 14 - 1.4

pH = 12.6

So the [H3O+] can be found by

pH = - log [H3O+]

12.6 = - log [H3O+]

Find the antilog of both sides

[H3O+] = 2.51 × 10^-13 M

Hope this helps you

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