joekeith998
joekeith998 joekeith998
  • 02-04-2020
  • Chemistry
contestada

How many moles of NaCl are in 2,719 mL of a 6.32 M solution?

Respuesta :

Tringa0 Tringa0
  • 03-04-2020

Answer:

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

Explanation:

[tex]Molarity=\frac{\text{Moles of substance}}{\text{Volume of solution in L}}[/tex]

We have:

Molarity of the NaCl solution = 6.32 M

Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L

1 mL = 0.001 L

Let the moles of NaCl be n.

[tex]6.32 M=\frac{n}{2.719 L}[/tex]

[tex]n=6.32M\times 2.719 L=17.18 mol[/tex]

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

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