jmharveyrn48 jmharveyrn48

02-03-2020
Engineering

contestada

P(5)=(0.11 x14)^5/5!e-^0.11-14

Respuesta :

07-03-2020

Answer:

The value of P(5)=0.09264

Explanation:

The equation given is;

[tex]P(5)=\frac{(0.11*14)^5}{5!e^-0.11-14} \\\\\\P(5)=(1.54)^5/120*2.7183^{-0.11} -14\\\\\\P(5)=8.662/120*0.8958-14\\\\\\P(5)=8.662/107.5-14\\\\P(5)=8.662/93.5\\\\P(5)=0.09264[/tex]

The value of P(5)=0.09264

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