leahdecker29 leahdecker29
  • 03-02-2020
  • Mathematics
contestada

find the distance (-4,5) and (7,18)

Respuesta :

frika
frika frika
  • 10-02-2020

Answer:

[tex]\sqrt{290}\ units[/tex]

Step-by-step explanation:

The distance between points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is

[tex]\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]

Hence, the distance between points [tex](-4,5)[/tex] and [tex](7,18)[/tex] is

[tex]\sqrt{(-4-7)^2+(5-18)^2}\\ \\=\sqrt{(-11)^2+(-13)^2}\\ \\=\sqrt{121+169}\\ \\=\sqrt{290}\ units[/tex]

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