stellalim2006 stellalim2006

02-02-2020
Mathematics

contestada

6j-k=23
3k+6j=11
Solve j and k using the elimination method on the simultaneous equations

Respuesta :

texaschic101 texaschic101

02-02-2020

Answer:

Step-by-step explanation:

6j - k = 23

6j + 3k = 11.....multiply by -1

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6j - k = 23

-6j - 3k = -11 (result of multiplying by -1)

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-4k = 12

k = -12/4

k = - 3 <=====

6j - k = 23

6j - (-3) = 23

6j + 3 = 23

6j = 23 - 3

6j = 20

j = 20/6

j = 10/3 <===

solution is : j = 10/3 and k = -3

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