atifgujar atifgujar
  • 01-05-2019
  • Mathematics
contestada

Find center and radius
(x-3)^2+y^2=8

Respuesta :

gmany
gmany gmany
  • 01-05-2019

Answer:

Center: (3, 0)

Radius: 2√2

Step-by-step explanation:

The equation of a circle in standard form:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

(h, k) - center

r - radius

We have the equation:

[tex](x-3)^2+y^2=8\to(x-3)^2+(y-0)^2=(\sqrt8)^2[/tex]

Therefore

the center: [tex](3,\ 0)[/tex]

the radius: [tex]r=\sqrt8\to r=\sqrt{4\cdot2}\to r=\sqrt4\cdot\sqrt2\to r=2\sqrt2[/tex]

Answer Link

Otras preguntas

I need help with this Q as I do not understand it
An empty box weighs 200g the box is filled with birthday party goozy bags and now weighs 6.2kg Each goody bag weighs 150Work out how many goody bags are inside
∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 28°, minor arc AB = 112°, and minor arc DE = 112°, what is the measure of ∠ACE
which best reaveals an instance of irony in "After Twenty Years"
what is the y intercept of -16t<2+150
In which of the following fields was Elisabeth Kübler-Ross a pioneer? denial depression acceptance bereavement
Why is a high use of renewable energy necessary to make hydrogen fuel an environmentally sound alternative? Respond in one complete paragraph.
Which speaker succeeds in changing the bride’s outlook in “Woo’d and Married and A’”?
The major purpose of the federal reserve buying government securities in open market operations is to
which best reaveals an instance of irony in "After Twenty Years"