Lon15
Lon15 Lon15
  • 02-04-2019
  • Mathematics
contestada

Solve for A ?

Anyone willing to help me :)

Solve for A Anyone willing to help me class=

Respuesta :

gmany
gmany gmany
  • 02-04-2019

Answer:

2.2

Step-by-step explanation:

Use the cosine law:

[tex]BC^2=AB^2+AC^2-2(AB)(AC)\cos(\angle A)[/tex]

We have:

[tex]BC=a\\\\AB=4\\\\AC=3\\\\m\angle A=32^o\to\cos32^o\approx0.848[/tex]

Substitute:

[tex]a^2=4^2+3^2-2(4)(3)(0.848)\\\\a^2=16+9-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2[/tex]

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