jaygriffo05 jaygriffo05
  • 01-10-2018
  • Mathematics
contestada

solve for p(x)
p(x)=(x^2+x+2)-[2x^2+2(-2x-4)]

Respuesta :

diyakmenon2004
diyakmenon2004 diyakmenon2004
  • 05-10-2018

This question can be solved through trial and error method looking at the closest possibilities.

p(x)= (x^2 + x+2)- ( 2x^2 +2(-2x -4))

= (x^2 + x+2) - (2x^2 -4x -8)   ( simplify inner brackets)

if x+2=0, x=(-2) ; p(x)= (-2)

( (-2)^2 + (-2)+2 ) - (2X(-2)^2 - 4X(-2) - 8)   ( solve brackets using BODMAS rule)

(4+0) - (2X2 + 8-8)

4-4

= 0

therefore x= (-2)



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