kingdede7667 kingdede7667
  • 04-08-2018
  • Mathematics
contestada

Find the polar equation for the cartesian curve x^2-y^2 = sqrt(x^2+y^2)

Respuesta :

valetta valetta
  • 04-08-2018

ANSWER:

r = [tex] \frac{1}{cos2(theta)} [/tex]

Explaination:

Convert the given curve into the the polar form.

x = rcosθ

y = rsinθ

in f(x,y) = (x²-y²) - √(x²+y²) = 0

put the values of x & y in given curve equation.

We get at,

g(r,θ) = (r²cos²θ - r²sin²θ) - √(r²cos²θ + r²sin²θ) = 0

g(r,θ) = r²(cos²θ - sin²θ) - √r² = 0

We know that,

cos²θ - sin²θ = cos2θ

g(r,θ) = r²(cos2θ) - r = 0

Solve for r

Finally we get:

r = [tex] \frac{1}{cos2(theta)} [/tex]

Ver imagen valetta
Answer Link

Otras preguntas

Regarding a living will, what can someone with power of attorney do? O A. Make important decisions for you if you cannot O B. Decide which parts of your savings
Organization that raises funds for presidential elections *
If 4x - y = 13 and 2x + y = 17 , then what does 3y - 2x = ?
After a head injury, gracie bloume begins speech therapy to assist with the condition of difficulty with speech. This condition is called.
how long is the peppermint milkshake at chick fil a
What are the search results of each Boolean operator?
PLEASE HELP WILL MARK BRAINLIEST AND GIVE 5.0 STAR RATING
The safety equipment must ………………. Inside the lab at all time brainly.
In a study reported in this module on unsafe work practices, researchers were observed doing this 2. 6 times per observation on average while handling human pat
Please help Step by step