Respuesta :

sqdancefan

[tex]\displaystyle\frac{\left(\frac{3x^2}{x^2+5x-6}\right)}{\left(\frac{6x^2-15x}{x^2+5x-6}\right)}=\frac{3x^2}{x^2+5x-6}\cdot\frac{x^2+5x-6}{6x^2-15x}\\\\=\frac{\left(x^2+5x-6\right)\left(3x^2\right)}{\left(x^2+5x-6\right)\left(6x^2-15x\right)}=\frac{3x(x)}{3x(2x-5)}\\\\=\frac{x}{2x-5}[/tex]

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